The sum of the first 6 terms of the arithmetic series with first term 4 and common difference 3 is:

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Multiple Choice

The sum of the first 6 terms of the arithmetic series with first term 4 and common difference 3 is:

Explanation:
The sum of an arithmetic series can be found quickly with S_n = n/2 [2a1 + (n−1)d]. Here a1 is 4, the common difference d is 3, and we want the first 6 terms. So S6 = 6/2 [2(4) + (6−1)·3] = 3 [8 + 15] = 3 · 23 = 69. The six terms themselves are 4, 7, 10, 13, 16, 19, which also add up to 69.

The sum of an arithmetic series can be found quickly with S_n = n/2 [2a1 + (n−1)d]. Here a1 is 4, the common difference d is 3, and we want the first 6 terms. So S6 = 6/2 [2(4) + (6−1)·3] = 3 [8 + 15] = 3 · 23 = 69. The six terms themselves are 4, 7, 10, 13, 16, 19, which also add up to 69.

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